2x^2+34x-335=0

Solution for 2x^2+34x-335=0 equation:

2x^2+34x-335=0

a = 2; b = 34; c = -335;
Δ = b2-4ac
Δ = 342-4·2·(-335)
Δ = 3836
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3836}=\sqrt{4*959}=\sqrt{4}*\sqrt{959}=2\sqrt{959}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34)-2\sqrt{959}}{2*2}=\frac{-34-2\sqrt{959}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34)+2\sqrt{959}}{2*2}=\frac{-34+2\sqrt{959}}{4}
$